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12x^2-84x-96=0
a = 12; b = -84; c = -96;
Δ = b2-4ac
Δ = -842-4·12·(-96)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-108}{2*12}=\frac{-24}{24} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+108}{2*12}=\frac{192}{24} =8 $
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